x^2+18x+7=-3x^2+2x-9

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Solution for x^2+18x+7=-3x^2+2x-9 equation: 



x^2+18x+7=-3x^2+2x-9

We move all terms to the left:

x^2+18x+7-(-3x^2+2x-9)=0

We get rid of parentheses

x^2+3x^2-2x+18x+9+7=0

We add all the numbers together, and all the variables

4x^2+16x+16=0

a = 4; b = 16; c = +16;
Δ = b2-4ac
Δ = 162-4·4·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-16}{8}=-2$

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